-60x^2-8x+32=0

Solution for -60x^2-8x+32=0 equation:

-60x^2-8x+32=0

a = -60; b = -8; c = +32;
Δ = b2-4ac
Δ = -82-4·(-60)·32
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-88}{2*-60}=\frac{-80}{-120}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+88}{2*-60}=\frac{96}{-120}
=-4/5
$